SOLUTION: If the inventor in Exercise 53 charges $4 per unit, then her profit for producing and selling x units is given by the function:
P(x) = 2.25x – 7000
a. What is her profit if
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-> SOLUTION: If the inventor in Exercise 53 charges $4 per unit, then her profit for producing and selling x units is given by the function:
P(x) = 2.25x – 7000
a. What is her profit if
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Question 62735: If the inventor in Exercise 53 charges $4 per unit, then her profit for producing and selling x units is given by the function:
P(x) = 2.25x – 7000
a. What is her profit if she sells 2000 units?
b. What is her profit if she sells 5000 units?
c. What is the break-even point for sales?
You can put this solution on YOUR website! Substitute x= 2000 and x=5000 into the profit equation to solve the first two.
Part a)P(x) = 2.25*2000 – 7000 = -$2500 ie a loss of $2500
Part b)P(x) = 2.25*5000 – 7000 = $4250
Part c) The break even point has a profit of 0.
0 = 2.25*x – 7000 Add 7000 to each side
7000 = 2.25*x – 7000 + 7000
7000 = 2.25*x Divide each side by 2.25
x = 3111 Units
(Actually 3111 units makes a 25 cent loss and 3112 units makes a $2 profit)
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