SOLUTION: I am supposed to evaluate the given function with the following numbers for the equation listed below. f (0) f (5) f (-2) f(x) = x2 – 7x + 10 How do i do this??? Thank

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am supposed to evaluate the given function with the following numbers for the equation listed below. f (0) f (5) f (-2) f(x) = x2 – 7x + 10 How do i do this??? Thank       Log On


   

Question 62732: I am supposed to evaluate the given function with the following numbers for the equation listed below.
f (0)
f (5)
f (-2)

f(x) = x2 – 7x + 10
How do i do this??? Thank you so much!
Found 2 solutions by Cintchr, funmath:
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
Plug in the value .... since you were given three different values ... you need to work it 3 times.
1. +f%28x%29+=+x%5E2+%96+7x+%2B+10+
+f%280%29+=+0%5E2+%96+7%280%29+%2B+10+
+f%280%29+=+0+-+0+%2B+10+
+f%280%29+=+10+
2. +f%28x%29+=+x%5E2+%96+7x+%2B+10+
+f%285%29+=+5%5E2+%96+7%285%29+%2B+10+
+f%285%29+=+25+-+35+%2B+10+
+f%285%29+=+-10+%2B+10+
+f%285%29+=+0+
3. +f%28x%29+=+x%5E2+%96+7x+%2B+10+
+f%28-2%29+=+-2%5E2+%96+7%28-2%29+%2B+10+
+f%28-2%29+=+4+%2B+14+%2B+10+
+f%28-2%29+=+18+%2B+10+
+f%28-2%29+=+28+

In essence, what we have created here is an X,Y table or a set of three ordered pairs
(0,10) (5,0) (-2,28)

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
I am supposed to evaluate the given function with the following numbers for the equation listed below.
f (0)
f (5)
f (-2)

f(x) = x^2 – 7x + 10
Substitute 0,5, and -2 in for x and simplify.
:
f(0)=(0)^2-7(0)+10
f(0)=0-0+10
f(0)=10
:
f(5)=(5)^2-7(5)+10
f(5)=25-35+10
f(5)=0
:
f(-2)=(-2)^2-7(-2)+10
f(-2)=4+14+10
f(-2)=28
:
Happy Calculating!!!!