SOLUTION: (4x-1)(x^2+5x-2)
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Question 627119
:
(4x-1)(x^2+5x-2)
Answer by
jim_thompson5910(35256)
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(4x-1)(x^2+5x-2)
4x(x^2+5x-2) - 1(x^2+5x-2)
4x(x^2)+4x(5x)4x(-2) - 1(x^2)-1(5x)-1(-2)
4x^3+20x^2-8x - 1x^2-5x+2
4x^3+19x^2-13x+2
So (4x-1)(x^2+5x-2) expands out to 4x^3+19x^2-13x+2