Question 626982: solve 2x-y+z=-7, x-3y+4z=-19, and -x+4y-3z=18
can someone show how they got the answer please, ty Found 2 solutions by ewatrrr, stanbon:Answer by ewatrrr(24785) (Show Source):
Hi,
solve by finding the value of 4 matrices
2x- y+ z=-7,
x-3y+4z=-19,
-x+4y-3z=18
A= |A|= a1(b2c3-c2b3) - b1(a2c3-c2a3) + c1(a2b3-b2a3) = -12
= 12 x = = -24 y = = 36 z =
You can put this solution on YOUR website! solve
2x-y+z=-7
x-3y+4z=-19
-x+4y-3z=18
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Rearrange the equations
x-3y+4z = -19
-x+4y-3z= 18
2x-y+z = -7
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Add 1st to 2nd
Subtract 2 times 1 from 3rd to get:
x - 3y + 4z = -19
0 + y + z = -1
0 + 5y - 7z = 41
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Subtract 5 times 2nd from 3rd to get:
x - 3y + 4z = -19
0 + y + z = -1
0 + 0 - 12z = 36
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Solve the 3rd equation for "z":
z = -3
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Substitute z = -3 into the 2nd equation
and solve for "y":
y = 2
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Substitute z = -3 and y = 2 into the 1st equation
and solve for "x":
x -3*2 + 4*-3 = -19
x -6 -12 = -19
x = -1
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Cheers,
Stan H.
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