SOLUTION: what is the length of the transverse axis of the hyperbola defined by the equation below? (y+3)^2/5^2-(x-5)^2/2^2=1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what is the length of the transverse axis of the hyperbola defined by the equation below? (y+3)^2/5^2-(x-5)^2/2^2=1      Log On


   

Question 626966: what is the length of the transverse axis of the hyperbola defined by the equation below? (y+3)^2/5^2-(x-5)^2/2^2=1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

%28y%2B3%29%5E2%2F5%5E2-%28x-5%29%5E2%2F2%5E2=1

 length of the transverse axis(distance between vertices) = 2·5 = 10

Standard Form of an Equation of an Hyperbola opening up and down is:

  %28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 with C(h,k) and vertices 'b' units up and down from center,  2b the length of the transverse axis

Foci sqrt%28a%5E2%2Bb%5E2%29units units up and down from center, along x = h

& Asymptotes Lines passing thru C(h,k), with slopes m =  ± b/a