SOLUTION: Find three consecutive even integers whose sum is 38 more than four times the largest integer.

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Question 626933: Find three consecutive even integers whose sum is 38 more than four times the largest integer.
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive even integers be: (2n-2), 2n and (2n+2).

Their sum = %282n-2%29+%2B+2n+%2B+%282n%2B2%29+=+6n
The largest integer = %282n%2B2%29

By problem i.e. Sum - 4 x Largest Integer = 38
6n+-+4%282n%2B2%29+=+38
6n+-+8n+-+8+=+38
2n+=+-38-8=-46

Thus, the three consecutive integers are: -48, -46 and -44