SOLUTION: Hi, may you please help me solve this problem. Thank you :) Find the perimeter of the triangle lying in xyz-space with vertices at points (7,2,3), (7, 14,3), and (12, 14, 3).

Algebra ->  Formulas -> SOLUTION: Hi, may you please help me solve this problem. Thank you :) Find the perimeter of the triangle lying in xyz-space with vertices at points (7,2,3), (7, 14,3), and (12, 14, 3).       Log On


   

Question 626855: Hi, may you please help me solve this problem. Thank you :)
Find the perimeter of the triangle lying in xyz-space with vertices at points (7,2,3), (7, 14,3), and (12, 14, 3).

Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
distance between (7,2,3) and (7,14,3) =sqrt%28%287-7%29%5E2+%2B+%282-14%29%5E2+%2B+%283-3%29%5E2%29= 12
distance between (7,2,3) and (12,14,3) =sqrt%28%287-12%29%5E2+%2B+%282-14%29%5E2+%2B+%283-3%29%5E2%29= 13
distance between (7,14,3) and (12,14,3) =sqrt%28%287-12%29%5E2+%2B+%2814-14%29%5E2+%2B+%283-3%29%5E2%29= 5
Add the 3 distances to get the perimeter
Perimeter = 12 + 13 + 5 = highlight%2830%29