SOLUTION: I hope this is in the right section.
13. divide
x^3+2x^2+x+12/x+3
I got as far as the first part. x^2 which gives us x^3 +3x^2. Do I add the 2x^2 to the 3x^2, giving me 5x
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: I hope this is in the right section.
13. divide
x^3+2x^2+x+12/x+3
I got as far as the first part. x^2 which gives us x^3 +3x^2. Do I add the 2x^2 to the 3x^2, giving me 5x
Log On
Question 62683This question is from textbook Beginning Algebra
: I hope this is in the right section.
13. divide
x^3+2x^2+x+12/x+3
I got as far as the first part. x^2 which gives us x^3 +3x^2. Do I add the 2x^2 to the 3x^2, giving me 5x^2 . If I am correct I didn't know what to do next with the x. This question is from textbook Beginning Algebra
You can put this solution on YOUR website! x^3+2x^2+x+12/x+3
I got as far as the first part. x^2 which gives us x^3 +3x^2. Do I add the 2x^2 to the 3x^2, giving me 5x^2 . If I am correct I didn't know what to do next with the x.
:
Long division;will use "......." to keep things lined up
:
.......................x^2 - x + 4
...........---------------------
(x+3)|x^3 + 2x^2 + x + 12
............x^3 + 3x^2
............------------- you subtract here
.....................-x^2 + x
.....................-x^2 -3x
......................-----------subtract here
................................+4x + 12
................................+4x + 12
.................................-------
........................................ 0
:
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