You can put this solution on YOUR website! How many milliliters of a 45% alcohol solution must be added to
10 milliliters of a 5% alcohol solution to produce a 20% alcohol solution?
:
let x = amt of 45% solution required
:
A simple mixture equation
.45x + .05(10) = .20(x+10)
.45x + .5 = .2x + 2
.45x - .2x = 2 - .5
.25x = 1.5
x = 1.5/.25
x = 6 ml required
:
:
Check this
.45(6) + .05(10) = .2(6+10)
2.7 + .5 = 3.2