SOLUTION: How do you condense this expression into a logarithm of a single quantity?
7[In z + In(z+7)]-6 In(z-5)= ???
I thought the answer would be something like this:
In((x^(-6)/
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-> SOLUTION: How do you condense this expression into a logarithm of a single quantity?
7[In z + In(z+7)]-6 In(z-5)= ???
I thought the answer would be something like this:
In((x^(-6)/
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Question 626769: How do you condense this expression into a logarithm of a single quantity?
7[In z + In(z+7)]-6 In(z-5)= ???
I thought the answer would be something like this:
In((x^(-6)/(z+7)*(z-5))^(7))
My answer automatically comes out to be wrong, though. I'm not sure how to answer this one. Please help me. Thank you!
- Cassidy Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Side note: Those are lowercase L's and not uppercase i's. So it's Ln (for natural log). I'm going to use uppercase L's for emphasis
7[Ln z + Ln(z+7)]-6 Ln(z-5)
7*Ln(z(z+7))-6*Ln(z-5)
7*Ln(z^2+7z)-6*Ln(z-5)
Ln((z^2+7z)^7)-Ln((z-5)^6)
Ln[ ((z^2+7z)^7/((z-5)^6) ]
So the answer is
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