SOLUTION: A room measures 18 ft wide, 30 ft long, and 10 ft high is painted. If there are 2 windows in the room each 7ft by 5ft and a glass door 6ft by 4ft then the area of wall space to be

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A room measures 18 ft wide, 30 ft long, and 10 ft high is painted. If there are 2 windows in the room each 7ft by 5ft and a glass door 6ft by 4ft then the area of wall space to be       Log On

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Question 626478: A room measures 18 ft wide, 30 ft long, and 10 ft high is painted. If there are 2 windows in the room each 7ft by 5ft and a glass door 6ft by 4ft then the area of wall space to be painted measures?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
One wall is 18*10 = 180 sq ft. So the opposite wall is also 180 sq ft

The other wall is 30*10 = 300 sq ft. The wall opposite that wall is also 300 sq ft

So the total area of all 4 walls is 180+180+300+300 = 960 sq ft

Now subtract off the areas of the windows of 7*5 = 35 sq ft to get 960 - 35 - 35 = 890 sq ft

and then subtract off the area of the 6*4 = 24 sq ft door to get 890 - 24 = 866

So the the area of wall space to be painted is 866 square feet
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