SOLUTION: A cylinder has its height doubled and its radius cut to one-third. What is the ratio of the volumes of the modified cylinder to the original cylinder?
I have the volume of the m
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I have the volume of the m
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Question 626344: A cylinder has its height doubled and its radius cut to one-third. What is the ratio of the volumes of the modified cylinder to the original cylinder?
I have the volume of the modified cylinder to be (pi)(1/9)(r^2)(2h) and the original cylinder to be (pi)(r^2)h.
Solving this my answer would be 18:1.
Is this correct?
Thanks Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A cylinder has its height doubled and its radius cut to one-third.
What is the ratio of the volumes of the modified cylinder to the original cylinder?
:
Let original cylinder have a radius of 9, a height of 10
: = = = 4.5 or a ratio of 9:2
