SOLUTION: the amount of radioactive tracer remaining after t days is given by A=A0e^-0.18t, where A0 is the starting amount at the beginning of the time period. How much could be acquired no
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-> SOLUTION: the amount of radioactive tracer remaining after t days is given by A=A0e^-0.18t, where A0 is the starting amount at the beginning of the time period. How much could be acquired no
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Question 62614: the amount of radioactive tracer remaining after t days is given by A=A0e^-0.18t, where A0 is the starting amount at the beginning of the time period. How much could be acquired now to have 40 grams remaining after 3 days?
You can put this solution on YOUR website! The amount of radioactive tracer remaining after t days is given by:
:
A=A0e^-0.18t,
where A0 is the starting amount at the beginning of the time period.
How much could be acquired now to have 40 grams remaining after 3 days?
:
That means A = 40, t = 3; find Ao
;
Ao * e^-.18(3) = 40
Ao * e^-54 = 40
find e^-.54 using a good calc
.582748Ao = 40
Ao = 40/.582748
Ao = 68.64 grams
:
Check: 68.64*e^-.54 = 39.99984 ~ 40
