SOLUTION: Hi, ive been asked to answer the following logarithm questions, with great difficulty, there doesnt seem any decent books out there, im just wondering if you could possibly help.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi, ive been asked to answer the following logarithm questions, with great difficulty, there doesnt seem any decent books out there, im just wondering if you could possibly help.       Log On


   



Question 62610: Hi, ive been asked to answer the following logarithm questions, with great difficulty, there doesnt seem any decent books out there, im just wondering if you could possibly help.
1) 3log(x-2) + 1/2log(x) ( that is half log(x) )
and
2) log(3xy) - log(x)
there is no "already answered questions" and i would be most gratefull of the answer or idea for the answer.
There is also another question which i would like your opinion and solution on,
it is
1) (5+j3)(3-j)-(3+j)
I have had many attempts at this coming up with such answers as
12 + j2 and 15 + j3 , am i on the right lines of thinking or completely wrong.
I am looking forward to you results and opinions which i will highly regard.
Thank you very much for your time.
regards
pete

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1) 3log(x-2) + 1/2log(x) ( that is half log(x) )
Usually the instructions for a problem like this is to
simplify this log expression. If that is the case here
the answer would be:
=log[(x-2)^2*(sqrtx)]
=log [(x^2-4x+4)*(sqrtx)]
--------------
2) log(3xy) - log(x)
=log[3xy/x]
=log(3y)
---------------
There is also another question which i would like your opinion and solution on,
it is
1) (5+j3)(3-j)-(3+j)
"j" usually means sqrt(-1)
If that is so for your problem you would get:
=(15-5j+9j+3)-(3+j)
=(18+4j)-(3+j)
=15+3j
-------
Hope this helps.
Cheers,
Stan H.