SOLUTION: If tan &#945; = 12/5, &#960; < &#945; < 3 &#960;/2, and sin &#946; = 2/3, 0< &#946; < &#960;/2, find A) sin &#945; B) cos &#946; C) cos 2 &#946; D) sin &#945;/2 E) cos (&#

Algebra ->  Trigonometry-basics -> SOLUTION: If tan &#945; = 12/5, &#960; < &#945; < 3 &#960;/2, and sin &#946; = 2/3, 0< &#946; < &#960;/2, find A) sin &#945; B) cos &#946; C) cos 2 &#946; D) sin &#945;/2 E) cos (&#      Log On


   



Question 625851: If tan α = 12/5, π < α < 3 π/2, and sin β = 2/3, 0< β < π/2, find
A) sin α
B) cos β
C) cos 2 β
D) sin α/2
E) cos (α+ β)
F) sin (α+ β)/2

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
If tan α = 12/5, π < α < 3 π/2, and sin β = 2/3, 0< β < π/2, find

We draw the graphs of the angles, alpha is in the third
quadrant and beta is in the first:

    

Next we draw perpendiculars to the x-axis, which creates right
triangles

    

Since the tangent is opposite/adjacent or y/x, we take the opposite side of 
alpha to be -12 (negative because it goes downward from the x-axis), and
the adjacent to be -5 (negative because it goes left from the origin).  

Since the sine is opposite/hypotenuse or y/r, we take the opposite side of 
beta to be +2 (positive because it goes upward from the x-axis), and
the hypotenuse r to be 3 (the hypotenuse r is ALWAYS taken positive).

    

Next we use the Pythagorean theorem to calculate the hypotenuse r for alpha
and the adjacent side x for beta.

r² = x² + y²            r² = x² + y²
r² = (-5)²+(-12)²       3² = x² + 2²
r² = 25 + 144            9 = x² + 4  
r² = 169                 5 = x² 
 r = 13                  sqrt%285%29 = x

    

Now we can answer the first two questions by merely looking at the triangles,
and knowing sine = opposite/hypotenuse and cosine = adjacent/hypotenuse,
using x for adjacent, y for opposite and r for hypotenuse:

 A) sin α = opp/hyp = y/r = (-12)/13 = -12/13
 B) cos β = adj/hyp = x/r = sqrt%285%29/3 

To do the others we have to use identities and then we can
substitute as above.  I will do C):

 C) cos 2β = cos²β-sin²β = (sqrt%285%29/3)²-(2/3)² = 5/9-4/9=1/9

Now you can do the others by yourself, using the proper identities and
the above graphs:

 D) sin α/2
 E) cos (α+β)
 F) sin (α+β)/2 

Edwin