Question 625843: Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one. Find the numbers Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! Numbers are n, n+2 and n+4
3n-7 = 2(n+4)
3n-7 = 2n+8
3n-2n = 8+7
n = 15
Answer: 15, 17 and 19
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