SOLUTION: the sum of three consecutive odd integers is 33. what is the product of the least and the greatest integer.

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Question 625744: the sum of three consecutive odd integers is 33. what is the product of the least and the greatest integer.
Found 3 solutions by Alan3354, sanadei, lenny460:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of three consecutive odd integers is 33. what is the product of the least and the greatest integer.
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Hint: 33/3 = 11, the middle integer

Answer by sanadei(3) About Me  (Show Source):
You can put this solution on YOUR website!
33/3=11=the middle number
:- the odd integers= 9,11,13.
Product of least and greates= 9 X 13= 117

Answer by lenny460(1073) About Me  (Show Source):
You can put this solution on YOUR website!
Let the three (3) consecutive odd integers be:
n + 1
n + 3
n + 5
Add the above:
3n + 9 = 33
Subtract 9 from each side of the equation
3n + 9 - 9 = 33 - 9
Combine like terms:
9 - 9 = 0
33 - 9 = 24
Therefore:
3n = 24
Divide each side by 3
3n/3 = 24/3
n = 8
Therefore:
n + 1 = 8 + 1 = 9
n + 3 = 8 + 3 = 11
n + 5 = 8 + 5 = 13
9 + 11 + 13 = 33
Therefore:
The three consecutive odd integers (numbers) are:

9, 11 and 13


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