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| Question 62568:   Find the midpoint of the line segment PQ for P(4, -3), Q(2, 7)
 
 If M (5, 2) is the midpoint of segment PQ and the coordinates of Q are (3,-3) , find the coordinates of P.
 
 Complete the ordered pairs so that each is a solution to the given linear equation. Present your answer as an ordered pair. 3x - 2y = 12
 (a) (-4, ?)          (b) (?, -3)
 
 Answer by funmath(2933)
      (Show Source): 
You can put this solution on YOUR website!  Find the midpoint of the line segment PQ for P(4, -3), Q(2, 7) The midpoint formula is midpoint=((x1+x2)/2,(y1+y2)/2)
 (x1,y1)=(4,-3) and (x2,y2)=(2,7)
 midpoint=((4+2)/2,(-3+7)/2)
 =(6/2,4/2)
 =(3,2)
 :
 If M (5, 2) is the midpoint of segment PQ and the coordinates of Q are (3,-3) , find the coordinates of P.
 The x coordinate of the midpoint is midpoint=(x1+x2)/2
 5=(3+x2)/2
 2(5)=2(3+x2)/2
 10=3+x2
 10-3=3-3+x2
 7=x2  This is the x coordinate of P
 The y coordinate of the midpoint is midpoint=(y1+y2)/2
 2=(-3+y2)/2
 2(2)=2(-3+y2)/2
 4=-3+y2
 4+3=-3+3+y2
 7=y2  This is the y coordinate of P
 P is (7,7)
 :
 
 Complete the ordered pairs so that each is a solution to the given linear equation. Present your answer as an ordered pair. 3x - 2y = 12
 (a) (-4, ?)
 Let x=-4 and solve for y.
 3(-4)-2y=12
 -12-2y=12
 -12+12-2y=12+12
 -2y=24
 -2y/-2=24/-2
 y=-12
 (-4,-12)
 :
 (b) (?, -3)
 Let y=-3 and solve for x
 3x-2(-3)=12
 3x+6=12
 3x+6-6=12-6
 3x=6
 3x/3=6/3
 x=2
 (2,-3)
 :
 Happy Calculating!!!
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