SOLUTION: find four consecutive even integers such that four times the fourth decreased by one-half (divided by 2) the second is 44.   x+2 x+4 x+6 x+8 4x + 8 -22 = 44 4x+44=44 4x+4

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: find four consecutive even integers such that four times the fourth decreased by one-half (divided by 2) the second is 44.   x+2 x+4 x+6 x+8 4x + 8 -22 = 44 4x+44=44 4x+4      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 625605: find four consecutive even integers such that four times the fourth decreased by one-half (divided by 2) the second is 44.
 
x+2 x+4 x+6 x+8
4x + 8 -22 = 44
4x+44=44 4x+44-44=44+44 4x=88, x =22
I just don't know what I am doing any help would be appreciated
Thank you,
Ruth
Answer by reynard2007(52) About Me  (Show Source):
You can put this solution on YOUR website!

Hi Ruth,
 
Since you are solving for even integers, let 2x be the first and then 2x+2, 2x+4 and 2x+6 the three that follow. We express the problem algebraically.
 
Four times the fourth: 4%282x%2B6%29
Half the second: %281%2F2%29%282x%2B2%29
Your equation should be: %284%282x%2B6%29%29-%281%2F2%29%282x%2B2%29=44
 
8x%2B24-x-1=44
7x%2B23=44
7x=21
Since x=3, the even numbers are 6, 8, 10, and 12.