SOLUTION: A car starting from rest moves down on an inclined road with a uniform acceleration . It travels for 100 m in 10 secs . The speed of car at the end of 10 sec is nearly a. 10 m/s

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Question 625553: A car starting from rest moves down on an inclined road with a uniform acceleration . It travels for 100 m in 10 secs . The speed of car at the end of 10 sec is nearly
a. 10 m/s
b. 20 m/s
c. 40 m/s
d. 100 m/s
its ans is b .. but i m not geting the correct ans , please help
Found 2 solutions by Alan3354, Emsley:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A car starting from rest moves down on an inclined road with a uniform acceleration . It travels for 100 m in 10 secs . The speed of car at the end of 10 sec is nearly
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Its average speed = 100/10 = 10 m/sec
It starts at zero --> end speed = 20 m/sec
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Or
s = at^2/2
a = 2s/t^2 = 200/100 = 2 m/sec/sec
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v = a*t = 2*10
v = 20 m/sec

Answer by Emsley(35) About Me  (Show Source):
You can put this solution on YOUR website!
S=1/2(u+v)t
So in this case 100=1/2*v*10 100=5v v=20