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| Question 62537:  Find thye polynomial f(x) of degree three that has zeroes at 1,2 and 4 such that f(0)= -16.
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Find the polynomial f(x) of degree three that has zeroes at 1,2 and 4 such that f(0)= -16. -----------
 f(x)=a(x-1)(x-2)(x-4)
 Then f(0)=a(-1)(-2)(-4)=-8a
 So, -8a=-16
 a=2
 Therefore f(x)=2(x-1)(x-2)(x-4)
 Cheers,
 Stan H.
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