SOLUTION: Find the consecutive numbers such that one- third the greater number exceeds one- fifth of the lesser number by 7.

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Question 625360: Find the consecutive numbers such that one- third the greater number exceeds one- fifth of the lesser number by 7.

Answer by reynard2007(52) About Me  (Show Source):
You can put this solution on YOUR website!

Let (x+1) and (x) be the consecutive numbers. We get one-thir of the bigger number by addin 7 to one-fifth of the smaller.
%281%2F3%29%28x%2B1%29=%281%2F5%29x%2B7
 
To get rid of the fractions, we multiply both sides of the equation by their LCD, 15. We get:
5%28x%2B1%29=3x%2B+105
5x%2B5=3x%2B105
2x=100
 
The consecutive numbers are 50 and 51. Just check the answer aainst the problem and tell me what happens. :D