Question 62530: A big jar contains four times as many quaters as pennies, three times as many nickels as dimes, and twice as many pennies as nickels. There are only pennies, nickels, dimes and quaters in this jar. THe total amoun in the jar is 25.24 find th number of pennies, nickels, dimes and quaters in this jar.
Please HElp!!!!
Found 2 solutions by stanbon, uma:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A big jar contains four times as many quaters as pennies, three times as many nickels as dimes, and twice as many pennies as nickels. There are only pennies, nickels, dimes and quaters in this jar. THe total amount in the jar is 25.24 find th number of pennies, nickels, dimes and quaters in this jar.
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Let number of nickels be "x": Value of these is 5x cents
Number of pennies is "2x" : Value of these is 2x cents
Numper of dimes is "x/3": Value of these is 10(x/3)cents
Number of auarters is "8x":Value of these is 25(8x)=200x cents
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EQUATION:
value + value+value+value = 2524 cents
5x+2x+(10x/3)+200x=2524
15x+6x+10x+600x=3*2524
631x=3*2524
x=12 (number of nickels.
2x=24 (number of pennies)
x/3=4 (number of dimes)
8x=96 (number of quarters)
Cheers,
Stan H.
Answer by uma(370) (Show Source):
You can put this solution on YOUR website!
Let the number of dimes be x.
So number of nickels = 3x.
Number of pennies = 6x
And number of quarters = 24x
Total amount in the jar = $25.24
= 2524 cents
Value of dimes = 10x
Value of nickels = 15x
value of quarters = 600x
Value of pennies = 6x
Thus 6x + 10x + 15x + 600x = 2524
==> 631x = 2524
==> 631x/631 = 2524/631
==> x = 4
Number of dimes = 4
Number of pennies = 24
Number of nickels = 12
Number of quarters = 96
Good Luck!!!
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