SOLUTION: (^13sqrt2x^6y)^5 rewrite with rational exponents

Algebra ->  Square-cubic-other-roots -> SOLUTION: (^13sqrt2x^6y)^5 rewrite with rational exponents      Log On


   



Question 625265: (^13sqrt2x^6y)^5 rewrite with rational exponents
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
"^13sqrt"???
Do you mean %28root%2813%2C+2x%5E6y%29%29%5E5? If yes, then
  • This is not a square root. It is a 13th root.
  • The 13 is not an exponent even though it may look like one. It is the "index" of the radical which indicates which kind of root it is.
  • To post problems with roots that are not square roots, do not use "sqrt" to describe it. For this problem you could either:
    • Use some English like: "(the 13th root of (2x^6y))^5"; or
    • Teach yourself the syntax used by algebra.com to display these mathematical expressions. Click on the "Show Source" link above to see what I typed to get the 13th root to display. Look for the expressions inside the sets of three braces: {...}

Radical expressions can be replaced with fractional/rational exponents. The fraction (or ratio) to use when replacing a radical with a rational exponent is 1 over the index of the radical. So to replace our radical with a rational exponent we will use 1/13:
%28%282x%5E6%2Ay%29%5E%281%2F13%29%29%5E5
Now we just use the power of a power rule for exponents (i.e. multiply the exponents:
%282x%5E6%2Ay%29%5E%285%2F13%29

P.S. Square roots do not have a visible index. For example: sqrt%282%29. A missing/invisible index is considered to be a 2. IOW, sqrt%282%29 means the same thing as root%282%2C+2%29. So the rational exponent for square roots is 1/2.