SOLUTION: If the ellipse defined by the equation 16x^2+4y^2+96x-8y+84=0 is translated 6 units down and 7 units to the left, write the standard equation of the resulting ellipse

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: If the ellipse defined by the equation 16x^2+4y^2+96x-8y+84=0 is translated 6 units down and 7 units to the left, write the standard equation of the resulting ellipse       Log On


   



Question 625240: If the ellipse defined by the equation 16x^2+4y^2+96x-8y+84=0 is translated 6 units down and 7 units to the left, write the standard equation of the resulting ellipse
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
16x² + 4y² + 96x - 8y + 84 = 0

Get the constant term off the left side by adding -84 to both sides

   16x² + 96x + 4y² - 8y = -84

Swap the two middle terms

   16x² + 96x + 4y² - 8y = -84

Factor out the coefficients of x² and y² 

16(x² + 6x) + 4(y² - 2y) = -84

To complete the square inside the first parenhtheses,
1. Multiply the coefficient of x, which is +6 by 1/2, getting 3
2. Square this result, (3)² = +9
3. Add +9 inside the first parentheses
4. Multiply +9 by the coefficient we factored out, 16, getting +144
5. Add +144 to the right side  

16(x² + 6x + 9) + 4(y² - 2y) = -84 + 144

To complete the square inside the second parenhtheses,
1. Multiply the coefficient of y, which is -2 by 1/2, getting -1
2. Square this result, (-1)² = +1
3. Add +9 inside the first parentheses
4. Multiply +1 by the coefficient we factored out, 4, getting +4
5. Add +4 to the right side  

16(x² + 6x + 9) + 4(y² - 2y + 1) = -84 + 144 + 4

Factor the 1st parentheses:  x² + 6x + 9 = (x + 3)(x + 3) = (x + 3)²
Factor the 2nd parentheses:  y² - 2x + 1 = (y - 1)(y - 1) = (y - 1)²
Combine terms on the right:  -84 + 144 + 4 = 64

16(x + 3)² + 4(y - 1)² = 64

Get a 1 on the right side by dividing through by 64

16%28x+%2B+3%29%5E2%2F64 + 4%28y+-+1%29%5E2%2F64 = 64%2F64

%28x+%2B+3%29%5E2%2F4 + %28y+-+1%29%5E2%2F16 = 1

%28x+%2B+3%29%5E2%2F2%5E2 + %28y+-+1%29%5E2%2F4%5E2 = 1

To translate this equation 6 units down and 7 units to the left,
replace y by (y+6) and x by (x+7)

%28%28x%2B7%29+%2B+3%29%5E2%2F2%5E2 + %28%28y%2B6%29+-+1%29%5E2%2F4%5E2 = 1

%28x%2B7+%2B+3%29%5E2%2F2%5E2 + %28y%2B6+-+1%29%5E2%2F4%5E2 = 1

%28x%2B10%29%5E2%2F2%5E2 + %28y%2B5%29%5E2%2F4%5E2 = 1

Edwin