SOLUTION: let me re-write the question which two tutors could not understand because of the student not using a proper notation, even it was more or less obvious what he meant: Question 624

Algebra ->  Trigonometry-basics -> SOLUTION: let me re-write the question which two tutors could not understand because of the student not using a proper notation, even it was more or less obvious what he meant: Question 624      Log On


   



Question 624976: let me re-write the question which two tutors could not understand because of the student not using a proper notation, even it was more or less obvious what he meant:
Question 624950:
If cos= 2 to the square root of 10/7 calculate the value of sin.
Should be posted this way:
If cos = (2 x sq.root(10))/7 calculate the value of sin. (answer is a.)
a. 3/7
b. square root of 29/7
c. square root of 69/7
d. square root of 89/7
Found 2 solutions by Alan3354, jsmallt9:

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
let me re-write the question which two tutors could not understand because of the student not using a proper notation, even it was more or less obvious what he meant:
Question 624950:
If cos= 2 to the square root of 10/7 calculate the value of sin.
Should be posted this way:
If cos = (2 x sq.root(10))/7 calculate the value of sin. (answer is a.)
a. 3/7
b. square root of 29/7
c. square root of 69/7
d. square root of 89/7
Found 2 solutions by Alan3354, jsmallt9:
-------------
The only thing obvious about it was that it made no sense.
Part of education is learning how to make sense, not speak gibberish.
---------
cos%28x%29+=+2sqrt%2810%29%2F7
sin%28x%29+=+sqrt%281+-+cos%5E2%28x%29%29
sin%28x%29+=+sqrt%28+1+-+40%2F49%29+=+sqrt%289%2F49%29
sin = 3/7 (principal value)

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Alan is 100% correct....it absolutely made no sense, to both tutors.

Are you actually trying to say that:

"If cos= 2 to the square root of 10/7 calculate the value of sin."

is the same as:

"If cos = (2 x sq.root(10))/7 calculate the value of sin"?

You must really be joking if you believe that.