SOLUTION: method of usbstitution 1:a=5-2b 5a+2b=1 2: 2m+n=0 m+2n=3 3: x+y=4 2x-y=5 4: y-2x=1 3x-4y=1 5: a-2b=9 2a+3b=4 6: x+2y=7 3x-2y=3 7: 2a+b=9 3a-2b=11

Algebra ->  Systems-of-equations -> SOLUTION: method of usbstitution 1:a=5-2b 5a+2b=1 2: 2m+n=0 m+2n=3 3: x+y=4 2x-y=5 4: y-2x=1 3x-4y=1 5: a-2b=9 2a+3b=4 6: x+2y=7 3x-2y=3 7: 2a+b=9 3a-2b=11      Log On


   



Question 624841: method of usbstitution
1:a=5-2b
5a+2b=1
2: 2m+n=0
m+2n=3
3: x+y=4
2x-y=5
4: y-2x=1
3x-4y=1
5: a-2b=9
2a+3b=4
6: x+2y=7
3x-2y=3
7: 2a+b=9
3a-2b=11

Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
method of usbstitution
1:a=5-2b
5a+2b=1
Sub for a in the 2nd eqn
5(5-2b) + 2b = 1
25-10b + 2b = 1
-8b = -24
b = 3
-----
a = 5-2b
a = -1
--------
2: 2m+n=0
m+2n=3
Solve either eqn for either m or n:
m+2n=3 --> m = 3-2n
Then it's the same as #1
========================
3 to 7 are the same as #2
-----
3: x+y=4
2x-y=5
4: y-2x=1
3x-4y=1
5: a-2b=9
2a+3b=4
6: x+2y=7
3x-2y=3
7: 2a+b=9
3a-2b=11

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
using Substitution to find the solution for the System:
couple of Exs:
1:a= highlight%285-2b%29 **
5a+2b=1, 5(highlight%285-2b%29) + 2b = 1
25-10b+2b=1
-8b = -24
b = 3 and a = -1 ||**a+=+5-2%2A3+=+-1
5: a-2b=9 'or' a = highlight%282b%2B9%29 **
2a+3b=4, 2(highlight%282b%2B9%29) + 3b = 4
4b +18 +3b = 4
7b = -14
b = 2 and a = 13 |||**a+=+2%2A2+%2B+9