SOLUTION: ((5x)((3y^2)/2)^(1/2))-((3y)((8x^2)/3)^(1/2))+((2)((3x^2y^2)/2)^(1/2))

Algebra ->  Radicals -> SOLUTION: ((5x)((3y^2)/2)^(1/2))-((3y)((8x^2)/3)^(1/2))+((2)((3x^2y^2)/2)^(1/2))      Log On


   



Question 624840: ((5x)((3y^2)/2)^(1/2))-((3y)((8x^2)/3)^(1/2))+((2)((3x^2y^2)/2)^(1/2))
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!

Since exponents of 1/2 mean the same thing as square roots, I am going to rewrite the expression with square roots:

Next we will simplify each square root. Part of simplifying square roots is rationalizing the denominators. There are a variety of ways to go about doing this. I like to start by making each denominator a perfect square:

which leads to:

Next we use the root%28a%2C+p%2Fq%29+=+root%28a%2C+p%29%2Froot%28a%2C+q%29 property of radicals to split each square root:

Because of our earlier work, each denominator will simplify:

Next we simplify the square roots in the numerators. Each one happens to have one or more prefect square factors (which I like to put first using the Commutative Property of Multiplication):

Now we use another property of radicals, root%28a%2C+p%2Aq%29+=+root%28a%2C+p%29%2Aroot%28a%2C+q%29, to split the square roots so that each perfect square factor is in its own square root:

Each of the square roots of the perfect squares simplify:

which simplifies further to:
%285xy%2Asqrt%286%29%29%2F2-%286xy%2Asqrt%286%29%29%2F3%2B%282xy%2Asqrt%286%29%29%2F2
The last two fractions reduce:
%285xy%2Asqrt%286%29%29%2F2-%282xy%2Asqrt%286%29%29%2B%28xy%2Asqrt%286%29%29
And last of all, these are all like terms! They are all xy%2Asqrt%286%29 terms. So we can add/subtract them. Just add/subtract the coefficients. To see this more easily, I'm going to rewrite the first and third terms so we can see the coefficient we should add:
%285%2F2%29xy%2Asqrt%286%29-%282xy%2Asqrt%286%29%29%2B%281xy%2Asqrt%286%29%29
which simplifies to:
%283%2F2%29xy%2Asqrt%286%29
since %285%2F2%29-2%2B1+=+3%2F2
So

simplifies to
%283%2F2%29xy%2Asqrt%286%29
or, if you prefer the 1/2 exponents:
%283%2F2%29xy%2A%286%29%5E%281%2F2%29