SOLUTION: Two trains run on same track and at rates 25 and 30 mph. If the slower trains starts 1 hour earlier how long will it take the for the faster train to catch up?
I can solve this pr
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I can solve this pr
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Question 624635: Two trains run on same track and at rates 25 and 30 mph. If the slower trains starts 1 hour earlier how long will it take the for the faster train to catch up?
I can solve this problem by
Slow 25 (x+1)
Fast 30 (x) 25x+25=30x -------- x =5
My questions is why can’t you solve it this way
Slow 25 (x)
Fast 30 (x-1) ----x=6 ??????????????????????????????
You can put this solution on YOUR website! Two trains run on same track and at rates 25 and 30 mph. If the slower trains starts 1 hour earlier how long will it take the for the faster train to catch up?
I can solve this problem by
Slow 25 (x+1)
Fast 30 (x) 25x+25=30x -------- x =5
=============
My questions is why can’t you solve it this way
Slow 25 (x)
Fast 30 (x-1) ----x=6 ??????????????????????????????
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Multiplying x-1 times 30 gives a headstart of 30 miles, not 25.
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Do it like this.
The 1st train is 25 miles away when the 2nd starts.
The 2nd gains in the 1st at 5 mi/hr (a better statement is the speed of the 2nd wrt to the 1st is 5 mi/hr, since all motion is relative)
25/5 = 5 hours.
You can put this solution on YOUR website! Two trains run on same track and at rates 25 and 30 mph. If the slower trains starts 1 hour earlier how long will it take the for the faster train to catch up?
I can solve this problem by
Slow 25 (x+1)
Fast 30 (x) 25x+25=30x -------- x =5
My questions is why can’t you solve it this way
Slow 25 (x)
Fast 30 (x-1) ----x=6 ??????????????????????????????
Your 1st method involved you making the time that the FASTER TRAIN takes to catch the slower train x, and this resulted in 5 hours. This is correct!!!
Your 2nd method is correct also. The only difference is that for the 2nd method you made the SLOWER TRAIN'S time to get to the "meeting point," x. This means that the time it took the slower train to get to the "meeting point" was 6 hours. All you need to realize now is that the time that the faster train will take to catch the slower train is (T - 1) hours, which resulted in a time of 5 (T - 1, or 6 - 1) hours.
You just need to remember the variables that you named.
I hope it's much clearer to you now!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
