SOLUTION: I need to factor the polynomials and solve the equation 32xy^3 +4x= I factored out 4x to get 4x(8y^3+1) but I am unsure if I should do that. Thanks in advance for

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need to factor the polynomials and solve the equation 32xy^3 +4x= I factored out 4x to get 4x(8y^3+1) but I am unsure if I should do that. Thanks in advance for      Log On


   

Question 624554: I need to factor the polynomials and solve the equation

32xy^3 +4x=

I factored out 4x to get 4x(8y^3+1)
but I am unsure if I should do that.
Thanks in advance for your help. Also can you please show me the steps.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Now let's factor 8y%5E3%2B1



8y%5E3%2B1 Start with the given expression.


%282y%29%5E3%2B%281%29%5E3 Rewrite 8y%5E3 as %282y%29%5E3. Rewrite 1 as %281%29%5E3.


%282y%2B1%29%28%282y%29%5E2-%282y%29%281%29%2B%281%29%5E2%29 Now factor by using the sum of cubes formula. Remember the sum of cubes formula is A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29


%282y%2B1%29%284y%5E2-2y%2B1%29 Multiply


So 8y%5E3%2B1 factors to %282y%2B1%29%284y%5E2-2y%2B1%29.

In other words, 8y%5E3%2B1=%282y%2B1%29%284y%5E2-2y%2B1%29


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Answer:

So in the end, 32xy%5E3+%2B4x completely factors to 4x%282y%2B1%29%284y%5E2-2y%2B1%29


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