SOLUTION: find the vertex, line of symmetry, min or max and graph. f(x)=-2x^2+2x+1

 

Hi,

find the vertex, line of symmetry, min or max and graph. 

f(x)= -2x^2+2x+1        |Completing square y = ax^2 + bx + c   ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c

f(x)= -2(x-1/2)^2 + 1/2 +1

  V(1/2,3/2,maximum   -2<0, parabola opens downward along x =.5



the vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

The standard form is , where  the focus is (h,k + p)



the vertex form of a Parabola opening right(a>0) or left(a<0),  

where(h,k) is the vertex and  y = k  is the Line of Symmetry

The standard form is , where  the focus is (h +p,k )