SOLUTION: solve for n: n= n^2-n

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Question 624392: solve for n: n= n^2-n
Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
n= n^2-n

0 = n^2-n-n

0 = n^2-2n

n^2-2n = 0

n(n-2) = 0

n = 0 or n-2 = 0

So the solutions are n = 0 or n = 2

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+n=+n%5E2-n+
Divide both sides by +n+
+1+=+n+-+1+
+n+=+2+
check answer:
+2+=+4+-+2+
OK
Does -2 work?
+-2+=+4+-%28-2%29+
+-2+=+6+
not true, still OK