SOLUTION: solve for n: n= n^2-n

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Question 624358: solve for n: n= n^2-n
Answer by jim_thompson5910(35256) About Me  (Show Source):
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n= n^2-n

0 = n^2-n-n

0 = n^2-2n

n^2-2n = 0

n(n-2) = 0

n = 0 or n-2 = 0

n = 0 or n = 2