SOLUTION: log(1-2x)-2logx = 1-log(2-5x)

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Question 624311: log(1-2x)-2logx = 1-log(2-5x)
Found 2 solutions by oscargut, ewatrrr:
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
log(1-2x)-2logx = 1-log(2-5x)
log(1-2x)-log(x^2) = log(10)-log(2-5x)
log((1-2x)/x^2) = log(10/(2-5x))
(1-2x)/x^2 = 10/(2-5x)
(1-2x)(2-5x)=10x^2

10x^2-9x+2 = 10x^2
-9x+2 = 0
x = 2/9
Answer: x = 2/9



Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

log(1-2x)-2logx = 1-log(2-5x)

log(1-2x)-2logx + log(2-5x) = 1

 log(1-2x)(2-5x)/x^2 = 1

 (1-2x)(2-5x)/x^2 = 10 

 (1-2x)(2-5x) = 10x^2 

  2 - 9x + 10x^2 = 10x^2

      2 = 9x

      2/9 = x