SOLUTION: A triangle has sides measuring 5, 12, and 15 units. Find all the angles of the triangle to the nearest tenth of a degree.
I beleive it's a SSS Triangle
b^2=a^2=+C^2-2ac COS B
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-> SOLUTION: A triangle has sides measuring 5, 12, and 15 units. Find all the angles of the triangle to the nearest tenth of a degree.
I beleive it's a SSS Triangle
b^2=a^2=+C^2-2ac COS B
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Question 624227: A triangle has sides measuring 5, 12, and 15 units. Find all the angles of the triangle to the nearest tenth of a degree.
I beleive it's a SSS Triangle
b^2=a^2=+C^2-2ac COS B
Cos B=12^2+15^2-5^2/2(12)(15) =144+225-25/360
=344/360
B=17.14
Sin A=12Sin17.14/5=0.7056
A=45
C117.9 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A triangle has sides measuring 5, 12, and 15 units. Find all the angles of the triangle to the nearest tenth of a degree.
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It is SSS.
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17.1 degs
45.0 degs
117.8 degs
according to my Excel sheet
