SOLUTION: the present age of a man is three times that of his son six years ago.the age of man was 4 times that of his son.find the ratio of their ages 6 yrs later
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Question 624150: the present age of a man is three times that of his son six years ago.the age of man was 4 times that of his son.find the ratio of their ages 6 yrs later Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! the present age of a man is three times that of his son. Six years ago.the age of man was 4 times that of his son.find the ratio of their ages 6 yrs later
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let x=son's present age
3x=father's present age
..
6 yrs ago
(x-6)=son's age
(3x-6)=father's age
(3x-6)/(x-6)=4
3x-6=4x-24
x=18
3x=54
..
6 yrs later
(x+6)=son's age
(3x+6)=father's age
(3x+6)/(x+6)
=(54+6)/24
=60/24
=5/2
ratio of father's age/son's age 6 yrs later=5/2
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