SOLUTION: What is the value of x in the equation 5^x+2 + 5^x+1 + 5^x = 3875?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: What is the value of x in the equation 5^x+2 + 5^x+1 + 5^x = 3875?      Log On


   

Question 623867: What is the value of x in the equation 5^x+2 + 5^x+1 + 5^x = 3875?
Found 2 solutions by lwsshak3, Emsley:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the value of x in the equation 5^x+2 + 5^x+1 + 5^x = 3875?
**
5^x+2 + 5^x+1 + 5^x = 3875
3(5^x)+3=3875
3(5^x)=3875-3=3872
5^x=3872/3
take log of both sides
xlog5=log3872-log3
x=(log3872-log3)/log5
x≈4.45

Answer by Emsley(35) About Me  (Show Source):
You can put this solution on YOUR website!
2*5^x+3=3875 2*5^x=3872 5^x=1936 Take logs of both sides log5^x=log1936
So xlog5=log1936 x=log1936/log5=4.702