SOLUTION: twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger find the lesser interger

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Question 62384: twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger find the lesser interger
Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
twice the lesser of two consecutive integers is 12 less than 3 times the greater integer find the lesser integer.
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Let the consecutive integers be x and x+1.
EQUATION:
2x+12=3(x+1)
2x+12=3x+3
2x=9
x=4.5
4.5 is not an integer.
Check the wording of your problem.
Cheers,
Stan H.

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger find the lesser interger
Let the first integer be: x
Then the second integer is:x+1
Twice the lesser is:2x
12 less than 3 times the greater is: 3(x+1)-12
is means:=
2x=3(x+1)-12
2x=3x+3-12
2x=3x-9
2x-3x=-3x+3x-9
-x=-9
-x/-1=-9/-1
x=9
The lesser integer is 9
Sanity check:
If the smaller integer is 9, then the greater integer is 10. Is twice the smaller integer equal to 3 times the greater integer less 12?
2(9)=3(10)-12
18=30-12
18=18 Looks good.
Happy Calculating!!!