SOLUTION: Dear All, I wish if you could help me understand below, please? The problem says: Line X has a slope of 3. The line passes through Point X at (-2,-1) and also passes through

Algebra ->  Coordinate-system -> SOLUTION: Dear All, I wish if you could help me understand below, please? The problem says: Line X has a slope of 3. The line passes through Point X at (-2,-1) and also passes through       Log On


   



Question 623677: Dear All,
I wish if you could help me understand below, please?
The problem says: Line X has a slope of 3. The line passes through Point X at (-2,-1) and also passes through Point Z., which has an x-coordinate of 0. What are the coordinates of Point Z?
So I guess that I have to substitute the given values in the formula m=Y2-y1 / X2-X1 (sorry I could not find the small 2s and 1s in my keyboard). So I got: 3= -1-y/-2-0 then 3= -1-y / -2 and after that I am stuck. I do not know how to find the Y value.
Many thanks for your help.
Ilda

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Line X has a slope of 3. The line passes through Point X at (-2,-1) and also passes through Point Z., which has an x-coordinate of 0. What are the coordinates of Point Z?
----------------
Step 1: Use the point and y = mx + b to find b, the y-intercept
-1 = 3*(-2) + b
b = 5
------
That makes the eqn of the line thru the point
y = 3x + 5
================
Sub 0 for x
--> y = 5
Point Z is (0,5)

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Dear All,
I wish if you could help me understand below, please?
The problem says: Line X has a slope of 3. The line passes through Point X at (-2,-1) and also passes through Point Z., which has an x-coordinate of 0. What are the coordinates of Point Z?
So I guess that I have to substitute the given values in the formula m=Y2-y1 / X2-X1 (sorry I could not find the small 2s and 1s in my keyboard). So I got: 3= -1-y/-2-0 then 3= -1-y / -2 and after that I am stuck. I do not know how to find the Y value.
Many thanks for your help.
Ilda

What you're trying to find is y%5B2%5D, the 2nd y-coordinate of the line

What you have is: 3+=+%28-+1+-+y%5B2%5D%29%2F%28-+2%29

-+6+=+-+1+-+y%5B2%5D ----- Cross-multiplying

-+6+%2B+1+=+-+y%5B2%5D

-+5+=+-+y%5B2%5D

%28-+5%29%2F-+1+=+y%5B2%5D

5+=+y%5B2%5D

Since y%5B2%5D = 5, then coordinate point of Z = (highlight_green%280%29,highlight_green%285%29)

Note:
The fact that Z's x-coordinate is 0 signifies that Z is the y-intercept. Therefore, the general form of the equation of a line (y = mx + b) should be used to solve for b, which would give the y-coordinate of Z. This is much easier, but only because itw's given that Z's x-coordinate is 0.

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