SOLUTION: What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1?

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Question 623432: What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1?
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
ln(x + 6) – ln(2x – 1) = 1

ln[(x + 6)/(2x – 1)] = 1

(x + 6)/(2x – 1) = e^1

(x + 6)/(2x – 1) = e

x + 6 = e(2x – 1)

x + 6 = 2ex – e

x - 2ex = – e - 6

x(1 - 2e) = – e - 6

x = (–e - 6)/(1 - 2e)

So the solution is x+=+%28-e+-+6%29%2F%281+-+2e%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1?
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ln (x + 6) – ln (2x – 1) = 1
ln ((x + 6)/(2x – 1)) = 1
(x + 6)/(2x – 1) = e
x + 6 = e*(2x – 1) = e*2x - e
x - 2e*x = -e - 6
x*(2e - 1) = e + 6
x = (e+6)/(2e-1)
x =~ 1.96509788