SOLUTION: May you help me solve this question? The question is 3[x-2y(x+2y)-3y^2)]. Thanks! :)

Algebra ->  Exponents -> SOLUTION: May you help me solve this question? The question is 3[x-2y(x+2y)-3y^2)]. Thanks! :)       Log On


   

Question 62328: May you help me solve this question? The question is 3[x-2y(x+2y)-3y^2)].
Thanks! :)
Answer by 303795(602) About Me  (Show Source):
You can put this solution on YOUR website!
3%28x-2y%28x%2B2y%29-3y%5E2%29%29 Expand the brackets working from the inside of the expression to the outside. This means the part to work on is -2y%28x%2B2y%29.Remember that the minus sign in front of the 2 belongs to the 2 when doing the multiplication.
-2y+%2A+x+=+-2xy and -2y+%2A+2y+=+-4y%5E2 so the expression is now
3%28x-2xy-4y%5E2-3y%5E2%29 Simply to two y squareds inside the brackets
3%28x-2xy-7y%5E2%29 Now multiply the 3 by each term inside the bracket
3x-6xy-21y%5E2