SOLUTION: a jar contains 84 coins: 19 quarters, 30 dimes, 12 nickles, and 23 pennies. What is the probability of selecting either a nickel or a penny?

Algebra ->  Probability-and-statistics -> SOLUTION: a jar contains 84 coins: 19 quarters, 30 dimes, 12 nickles, and 23 pennies. What is the probability of selecting either a nickel or a penny?      Log On


   

Question 623249: a jar contains 84 coins: 19 quarters, 30 dimes, 12 nickles, and 23 pennies. What is the probability of selecting either a nickel or a penny?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,  

a jar contains 84 coins: 19 quarters, 30 dimes, 12 nickles, and 23 pennies. 

P(nickel or Penny)= P(nickel) + P(Penny) = %2812%2F84%29+%2B+%2823%2F84%29+=+35%2F84+=+5%2F12