You can put this solution on YOUR website! write the expression 3log3x+2log3y-1/3log3x6-log1231 as a logarithm of a single quantity.
Something seems wrong with the last term because the logs have to all have the same bases to write them as a single quantity. I am assuming that the base of the other logs is 3, let me know if I'm mistaken.
log3(x^3)+log3(y^2)-log3(x^(6(1/3))-log3(1231)
log3(x^3)+log3(y^2)-log3(x^2)-log3(1231)
log3(x^3)+log3(y^2)-(log3(x^2)+log3(1231))
log3(x^3y^2)-log3(1231x^2)
log3()
log3()
Happy Calculating!!!
Let me know if I misinterpretted your problem. I hope you can understand the way I typed my logs.
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