SOLUTION: this is for college algebra: verify that 3i is a zero of p(x) = x^3 - 5x^2 + 9x - 45 then use the conjugate pair theorem to find the remaining zeros

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Question 62303: this is for college algebra: verify that 3i is a zero of p(x) = x^3 - 5x^2 + 9x - 45 then use the conjugate pair theorem to find the remaining zeros
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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this is for college algebra: verify that 3i is a zero of p(x) = x^3 - 5x^2 + 9x - 45 then use the conjugate pair theorem to find the remaining zeros
:
Find the equation that produced x = +/-3i
x = +/-3i
Square both sides:
x^2 = 9*i^2
x^2 = 9*(-1)
x^2 = -9
(x^2 + 9) = 0
:
The final term is -45 so the other factor has to be (x-5):
(x-5)*(x^2 + 9) = 0
:
FOIL this and you get x^3 - 5x^2 + 9x - 45
:
x = +5 is the zero
:
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