SOLUTION: Given: side b = 600, angle B = 11 degrees, angle C = 75degrees in triangle ABC; find side a and side c. (Round the answer to the nearest whole number.)

Algebra ->  Triangles -> SOLUTION: Given: side b = 600, angle B = 11 degrees, angle C = 75degrees in triangle ABC; find side a and side c. (Round the answer to the nearest whole number.)      Log On


   

Question 622981: Given: side b = 600, angle B = 11 degrees, angle C = 75degrees in triangle ABC; find side a and side c. (Round the answer to the nearest whole number.)
Found 2 solutions by Alan3354, Earlsdon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Given: side b = 600, angle B = 11 degrees, angle C = 75degrees in triangle ABC; find side a and side c. (Round the answer to the nearest whole number.)
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Angle A = 180 - (B+C) = 94 degs
a/sin(A) = b/sin(B)
a = 600*sin(94)/sin(11)
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Find c the same way.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You can use "the law of sines" to solve this.
SinB%2Fb+=+SinC%2Fc Solve for c.
c+=+bSinC%2FSinB Substitute b = 600, C = 75 degrees, and B = 11 degrees.
c+=+600%28Sin75%2FSin11%29
c+=+3037.36
c+=+3037 Rounded to nearesst whole number.