SOLUTION: solve: logx + log(x+3)= 1

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Question 622911: solve:
logx + log(x+3)= 1
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
logx + log(x+3)= 1
logx(x+3)= 1
x(x+3)= 10^1
x^2+3x = 10
x^2+3x-10 = 0
(x+5)(x-2) = 0
x = {-5, 2}
throw out the negative solution (extraneous) leaving:
x = 2