SOLUTION: Shreya mixed together 3 L of brand A fruit drink and 5 L of brand B fruit drink which contains 50% fruit juice. Find the percent of fruit juice in brand A if the mixture con tainte

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Question 622885: Shreya mixed together 3 L of brand A fruit drink and 5 L of brand B fruit drink which contains 50% fruit juice. Find the percent of fruit juice in brand A if the mixture con tainted 44% fruit juice.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of juice in 3 L of brand A
+.5%2A5+=+2.5+ liters of juice in 5 L of brand B
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+%28+x+%2B+2.5+%29+%2F+%28+3+%2B+5+%29+=+.44+
+%28+x+%2B+2.5+%29+%2F+8+=+.44+
+x+%2B+2.5+=+3.52+
+x+=+3.52+-+2.5+
+x+=+1.02+
There are 1.02 liters of juice in 3 L of brand A
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+1.02+%2F+3+=+.34+
Brand A mixture has 34% fruit juice
check answer:
+%28+x+%2B+2.5+%29+%2F+8+=+.44+
+%28+1.02+%2B+2.5+%29+%2F+8+=+.44+
+3.52+%2F+8+=+.44+
+3.52+=+8%2A.44+
+3.52+=+3.52+
OK