SOLUTION: Cant figure this one out. Find the vertical and horizontal asymptotes of y=(5x^2-8x+1)/(2x^2-5x-12) thank you

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Question 62284: Cant figure this one out.
Find the vertical and horizontal asymptotes of y=(5x^2-8x+1)/(2x^2-5x-12)
thank you
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertical and horizontal asymptotes of y=(5x^2-8x+1)/(2x^2-5x-12)
When the degree of the numerator and denominator are the same, the horizontal asymptote will be at their leading coefficients: y=5/2
There is a vertical asymptote anywhere that it is undefined once it's factored and simplified.
y=%285x%5E2-8x%2B1%29%2F%28%282x%5E2-8x%2B3x-12%29%29
y=%285x%5E2-8x%2B1%29%2F%282x%28x-4%29%2B3%28x-4%29%29
y=%285x%5E2-8x%2B1%29%2F%28%282x%2B3%29%28x-4%29%29
There are two vertical asymptotes:
2x+3=0 and x-4=0
2x=-3 and x=4
x=-3/2 and x=4
Here's what it looks like:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%285x%5E2-8x%2B1%29%2F%282x%5E2-5x-12%29%29
Happy Calculating!!!