SOLUTION: Find an equation of the line having the given slope and containing the given point. m=5, (4,1) The equation of the line in slope intercept form is y= There parts I understand an

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Find an equation of the line having the given slope and containing the given point. m=5, (4,1) The equation of the line in slope intercept form is y= There parts I understand an      Log On


   



Question 622748: Find an equation of the line having the given slope and containing the given point. m=5, (4,1) The equation of the line in slope intercept form is y=
There parts I understand and some I do not. Here is what I attempted to do to solve the problem
m= 5, (4, 1)
m=5 and y intercept (4,1)
m=5 and b=1
y=4 times x +1 (this is the part I did not understand)
y=1

Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find an equation of the line having the given slope and containing the given point. m=5, (4,1)
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Use y = mx + b and the point to find b
1 = 5*4 + b
b = -19
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Then just write it:
y = 5x - 19

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Line with m = 5 and passing thru (4,1)
General format for an Equation of a Line is: y+=+highlight%28m%29x+%2B+b
This Line: m = 5
y = 5x + b | Using Pt(4,1) to solve for b
1+=+5%2A4+%2B+b
1 = 20 + b
-19 = b
y = 5x -19