SOLUTION: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
Log On
Question 62268: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time? Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! Distance = (Rate)(Time) [Use the distance formula]
28 miles = (rate)(30 minutes X 1 hour/60 minutes)[plug-in the values; change minutes to hours and solve]
.
28=(r)(.5)
28=.5r [solve for the rate (r)
28/.5=r
56 miles per hour = r
.
Check by plugging in all of the values back into the original equation:
d=rt
28=(56)(.5)
28=28 [checks out]